Here is the popular modular-exponentiation function. So, the corresponding private key is (d = 1951097, n = 44331583).Ĭompute m**d (mod n) to decrypt an RSA message (a.k.a. That is, the inverse of e modulo φ(n) is d=1951097. """ display the inverse of e modulo phi """ The sender encrypt the message with its private key and the receiver decrypt with the sender's public key. Print(str(n) + " = " + str(i) + " * " + str(n // i)) This module demonstrates step-by-step encryption with the RSA Algorithm to ensure authenticity of message. Try harder before looking at the answer below. You should be able to do all the computations by simple programming using your favorite programming language and computer. The numbers used are not large enough to prevent you from obtaining the private key given the public key. However, the exercise assigned to you is designed for you to practice RSA algorithm. This should be too hard to do in practical situations in general, since RSA algorithms are time-tested field-tested security algorithms, and people are using it carefully with long-enough bits in general. ![]() ![]() Well, we have to find the private key from the public key. "How can we decrypt an RSA message if we only have the public key?"
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